Question

25.00 mL aliquot of 0.016 M NaCl was titrated with 27.52 mL of 0.18 M AgNO3. Determine whether a precipitate will form at end point. Ksp AgCl = 1.6 x10-10

Answer 1

AgNO₃ (aq) + NaCl (aq) → AgCl (s) + NaNO₃ (aq)

Moles of $NaCl =\frac {25×0.016}{1000}=0.0004moles$

Moles of $AgNO_3 =\frac {27.52×0.18}{1000}=0.005moles$

Yes precipitate will be formed