A solution of Ba(OH)2 was standardized against 0.1016g of primary standard benzoic acid C6H5COOH. Calculate the concentration of Ba(OH)2 if the end point was 20.89mL
Moles of Ba(OH)2=0.1016171.34=0.0006molesBa(OH)_2=\frac{0.1016}{171.34}=0.0006molesBa(OH)2=171.340.1016=0.0006moles
Molarity=0.00060.02089=0.03MMolarity= \frac{0.0006}{0.02089}=0.03MMolarity=0.020890.0006=0.03M
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