Question

a compound Y with chemical formula as shown below:

CH2=CHCOOCH3

b) calculate the percentage composition of carbon in the compound Y.

Answer 1

we will find it by the formula:

$w(C)=\frac{т\times Ar(C)}{Mr(CH2 = CHCOOCH3)}=\frac{4\times12}{86.09}=0.56$ or 56%

Mr(CH2 = CHCOOCH3)=86.09