a compound Y with chemical formula as shown below:
CH2=CHCOOCH3
b) calculate the percentage composition of carbon in the compound Y.
we will find it by the formula:
"w(C)=\\frac{\u0442\\times Ar(C)}{Mr(CH2 = CHCOOCH3)}=\\frac{4\\times12}{86.09}=0.56" or 56%
Mr(CH2 = CHCOOCH3)=86.09
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