Question

A compound is found to contain 15.12 % phosphorus, 6.841 % nitrogen, and 78.03 % bromine by mass.

Answer 1

Solution

P= 15.21%

N=6.841%

B=78.03%

Molar mass P=0.4881,N=0.4884,B=0.97

divide by the smallest number

$P=\frac{0.4881}{0.4881}=1$

$N=\frac{0.4884}{0.4881}=1$

$B= \frac{0.9765}{0.4881}= 2$

Empirical formula Br₂NP