Using mold concept, find the concentration of NaOH using 0.10 moldm2 given that the volume of acid used was 12.0cm volume of Base 25cm2
Using mole concept
Given that the chemical reaction is;
NaOH+HCl→NaCl+H2ONaOH +HCl\to NaCl + H_2 ONaOH+HCl→NaCl+H2O
CA=0.10 mol/dm³VA=12.0cm3VB=25cm3CB=?C_A = 0.10 \textsf{ mol/dm³}\\ V_A = 12.0cm³\\ V_B = 25cm³\\ C_B = ?CA=0.10 mol/dm³VA=12.0cm3VB=25cm3CB=?
CAVACBVB=nAnB\dfrac{C_AV_A}{C_BV_B} = \dfrac{n_A}{n_B}CBVBCAVA=nBnA
0.10×12CB×25=11\dfrac{0.10 × 12}{C_B × 25} = \dfrac11CB×250.10×12=11
CB=0.10×1225=0.048 mol/dm³C_B = \dfrac{0.10× 12}{25} = 0.048 \textsf{ mol/dm³}CB=250.10×12=0.048 mol/dm³
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