C3H8(g) + 5O2(g) 🡪 3CO2(g) + 4H2O(g)
Calculate the volume of carbon dioxide and water vapour produced and the volume of oxygen remaining, when 20.0 L of propane reacts with 120.0 L of oxygen at STP.
 Na2CO3(aq) + 2HCl(aq)  🡪  2NaCl(aq)  +  H2O(l)  +  CO2(g)
The volumes are all measured at the same conditions of temperature and pressure. This implies that mole ratios may be interpreted as volume ratios. Have
Volume of "Co_2 ={ 3}\u00d7 {20}=60" L
Volume of "H_2O=\\frac{120\u00d74}{5}=" 96L
"Na_2CO_3(aq) + 2HCl(aq) ---> 2NaCl(aq) + H_2O(l) + CO_2(g)"
Moles of sodium carbonate ="\\frac{100\u00d71.1}{1000}=0.11moles"
Moles of HCL"=\\frac{250\u00d71.15}{1000}=0.2875moles"
Moles of "CO_2=0.11"
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