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Answer to Question #220632 in General Chemistry for Nooner
Question #220632
What is the pH of a titration of 0.077 L of 0.5M HCl when 0.019 L of 0.25M NaOH have been added?
Expert's answer
0.5 - 0.25 = 0.25
0.25/0.096
2.604
PH + POH = 14
pOH=−log([OH-])
= -0.416
pH = 14+0.416
= 14.42
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