Answer to Question #220632 in General Chemistry for Nooner

Question

What is the pH of a titration of 0.077 L of 0.5M HCl when 0.019 L of 0.25M NaOH have been added?

Answer 1

0.5 - 0.25 = 0.25

0.25/0.096

2.604

PH + POH = 14

pOH=−log([OH^-])

= -0.416

pH = 14+0.416

= 14.42