Answer to Question #219262 in General Chemistry for daniela

Question #219262

Chloracetic acid is a stronger monoprotic acid than acetic acid. In a 0.10M solution of this acid, the pH was 1.96. Find the Ka. (Hint: you can use the general formula HA to represent chloroacetic acid)


1
Expert's answer
2021-07-21T04:37:20-0400


Equilibrium reaction


"HC_2H_2O_2Cl+H_2O->C_2H_2O_2Cl^-H_3O^+"


"Ka=\\frac{products}{reactants}"


"Ka=\\frac{[C_2H_2O_2CL^-][H_3O^+]}{[HC_2H_2O_2CL]}"


"Ka=\\frac{[X][X]}{0.10-X}"


"Ka=\\frac{X^2}{0.10-X}"


we can calculate the value of X using [H3O+] and the given pH of the solution

"[H^+]=[H_3O^+]"


"H_3O^+=10^{-pH}"


"H_3O^+=10^{-1.96}"

"H_3O^+=X=0.010965"


Hence


"Ka=\\frac{X^2}{0.10-X}"

"Ka=\\frac{[0.010965]^2}{0.10-[0.010956]}=1.35\\times{10^{-3}}"


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS