Answer to Question #218726 in General Chemistry for Bked

Question #218726

CH3NH2 + H2O <-> CH3NH3+ + OH-

Ka = 2.33x10^-11

Given the CH3NH2 concentration is 1.5M, what is the equilibrium concentration of Ch3NH2, CH3NH3+, OH-?

Expert's answer

2.33× 10^-11 = 1.5 × x

= 2.33/1.5

× = 1.533M

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