Question

how many moles of PCl₅ can be produced from 50.0 g of Cl₂

Answer 1

P₄+ 10Cl₂ → 4PCl₅

M(Cl₂)= 70.90 g/mol

M(PCl₅)=208.24 g/mol

$n = \frac{m}{M} \\$

n(Cl₂) $= \frac{50.0}{70.90}=0.705 \;mol$

According to the reaction:

n(PCl₅) $= \frac{4}{10}n(Cl_2) = \frac{4}{10} \times 0.705 = 0.282 \;mol$

m(PCl₅) $= 0.282 \times 208.24 = 58.74 \;g$

Answer: 58.74 g