Answer to Question #218315 in General Chemistry for Ma Corazon Partosa

Question

If 50 g of aluminum nitrite is reacted with 50g of ammonium chloride, how many grams of aluminum chloride will be produced?

Answer 1

Balanced equation: Al(NO₂)_3(aq) + 3 NH₄Cl_(aq) → AlCl_3(aq) + 3 N_2(g) + 6 H₂O_(l)

mole ratio between Aluminum nitrite : aluminum chloride = 1:1

50/212.996

Ratio between ammonium chloride: aluminum chloride = 3:1

50/53.491

Molar Mass of aluminum nitrite = 212.996

Molar Mass of ammonium chloride = 53.491

Molar Mass of aluminum chloride = 133.34

= 31.3+41.56

= 72.86g