2 Fe+2(aq) + H2O2(aq) ---> 2Fe+3(aq) + 2 OH-1(aq)
What is the oxidation state of oxygen in H2O2
Oxidation state of oxygen in H2O2.
Since hydrogen has an oxidation state of +1
Then we'll be having;
(1)2+O2=0
2 + O2 = O
Then bringing the constant to the right side have;
O2 = -2 Dividing both side by 2, we have;
O = -1
Therefore the oxidation state of Oxidation state of oxygen in H2O2 is -1
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