Calculate the standard entropy change for the following reaction:
Ca(OH)2(s) ⟶ CaO(s) + H2O(l)
ΔS0=S0(CaO)+S0(H2O)−S0(Ca(OH)2)=38.2+69.91−83.39=24.72 J/mol⋅KΔS^0 = S^0(CaO) + S^0(H_2O) -S^0(Ca(OH)_2) \\ = 38.2+ 69.91 -83.39 = 24.72 \; J/mol \cdot KΔS0=S0(CaO)+S0(H2O)−S0(Ca(OH)2)=38.2+69.91−83.39=24.72J/mol⋅K
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