What is the equilibrium constant for a reaction that has a value of Go = -41.8 kJ at 100oC?
∆G°=−RTInK∆G^°=-RTInK∆G°=−RTInK
∆G°=−41.8KJ=−41800J∆G^°=-41.8KJ=-41800J∆G°=−41.8KJ=−41800J
−41800J=−8.314×373×InK-41800J=-8.314\times373\times InK−41800J=−8.314×373×InK
InK=13.479InK=13.479InK=13.479
K=714258.3424K=714258.3424K=714258.3424
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