Question #213669

What is the equilibrium constant for a reaction that has a value of Go = -41.8 kJ at 100oC?


1
Expert's answer
2021-07-15T02:40:47-0400

G°=RTInK∆G^°=-RTInK

G°=41.8KJ=41800J∆G^°=-41.8KJ=-41800J

41800J=8.314×373×InK-41800J=-8.314\times373\times InK

InK=13.479InK=13.479

K=714258.3424K=714258.3424


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS