100 l helium gas at 30 degrees celsius and the pressure of 2.00atm was transferred to a tank with volume of 50.0 L, what is the internal pressure of the tank if the hotness is maintained
"V_1=100 \\;l \\\\\n\np_1 = 2.0 \\;atm \\\\\n\nV_2=50.0 \\;l \\\\\n\nt= 30 \\;C = constant \\\\\n\np_1V_1 = p_2V_2 \\\\\n\np_2 = \\frac{p_1V_1}{V_2} \\\\\n\np_2 = \\frac{2.0 \\times 100}{50.0}= 4 \\;atm"
Answer: 4 atm
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