Question

100 l helium gas at 30 degrees celsius and the pressure of 2.00atm was transferred to a tank with volume of 50.0 L, what is the internal pressure of the tank if the hotness is maintained

Answer 1

$V_1=100 \;l \\ p_1 = 2.0 \;atm \\ V_2=50.0 \;l \\ t= 30 \;C = constant \\ p_1V_1 = p_2V_2 \\ p_2 = \frac{p_1V_1}{V_2} \\ p_2 = \frac{2.0 \times 100}{50.0}= 4 \;atm$

Answer: 4 atm