(a) 0.1 mol of Lithium reacts with excess oxygen gas.
(i) Write a balanced chemical equation for the reaction.
(ii) Calculate the mass of the product formed.
[ Relative atomic mass : Lithium=7, Oxygen=16]
I) 4Li+O2=2Li2O4Li+O_2=2Li_2O4Li+O2=2Li2O
ii) Mass of the product formed=74.3g
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