Question

A household cleaner contains 4.25 g of ammonia in 0.50 L of solution. There are 17.01 g in 1 mol of ammonia. What is the concentration of ammonia in mol/L?

Answer 1

Solution

no of moles$=\frac{mass}{molar mass}=\frac{4.25}{17.01}$

= 0.2499 moles

molarity$=\frac{no of moles}{volume inL}= \frac{0.2499}{0.5}$

=0.4998 mol/L