How many moles of N2 reacted if 0.65 mol of NH3 is produced? Please answer in 2 significant figures
N2 + 3H2 → 2NH3
According to the reaction equation:
"n(N_2) = \\frac{1}{2}n(NH_3) = \\frac{1}{2} \\times 0.65 = 0.32 \\;mol"
Answer: 0.32 mol
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