How many moles of N2 reacted if 0.65 mol of NH3 is produced? Please answer in 2 significant figures
N2 + 3H2 → 2NH3
According to the reaction equation:
n(N2)=12n(NH3)=12×0.65=0.32 moln(N_2) = \frac{1}{2}n(NH_3) = \frac{1}{2} \times 0.65 = 0.32 \;moln(N2)=21n(NH3)=21×0.65=0.32mol
Answer: 0.32 mol
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