Answer to Question #210205 in General Chemistry for princess

Question

A standard NaOH solution was prepared by dissolving 0.05 mol of NaOH in 250 mL of

distilled water. 25 mL of the prepared NaOH solution was titrated with 0.15 M H2SO4

solution. Calculate the volume of H2SO4 solution that is required to reach the equivalence

point.

Answer 1

$H_2SO_4+ 2NaOH \to Na_2SO_4 +H_2O$

molarity of NaOH = $\dfrac{0.05}{250}× 1000 = 0.2M$

$\dfrac{c_Av_A}{c_Bv_B} = \dfrac{n_A}{n_B}$

$\dfrac{0.15× v_A}{0.2×25} =\dfrac12$

$v_A = \dfrac{0.2× 25}{0.15× 2} =\dfrac{5}{0.3} = 16.67mL$