If the pressure increases by half in C2H2 + O2 ⇆ CO2 + H20 ΔH = +
2C2H2(g)+5O2(g)→4CO2(g)+2H2O(g)2 C_2H_2 (g) + 5 O_{2 (g)} \to4 CO_{2 (g) }+ 2 H_2O_{(g)}2C2H2(g)+5O2(g)→4CO2(g)+2H2O(g)
If the pressure in the mixture/reaction increases by half, the rate of formation of the reactants would increase (by half).
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