An expandable balloon contains 3.50 dm3 of helium at 101. kPa and 23.0oC. What volume will the balloon occupy when the pressure drops to 85.0 kPa and the temperature is 10.0oC?
P1×V1T1=P2×V2T2\frac{P_1×V_1}{T_1}=\frac{P_2×V_2}{T_2}T1P1×V1=T2P2×V2
101×3.5296=85×V2283\frac{101×3.5}{296}=\frac{85×V_2}{283}296101×3.5=28385×V2
V2=3.98dm3V_2=3.98dm^3V2=3.98dm3
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