In the following chemical equation, find the mass of o2 required to react completely with a 20g sample of 80% purity by mass c6h12o6.
C6H12O6Â +Â O2Â = CO2 + H2O
Molar Mass of O2 = 32
Molar Mass of C6H12O6 = 180.156
80% of 180.156 = 144.125
20g of 144.125 = 2882.496
= 2882.296 g of O2
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