Two reactions and their equilibrium constants are given.
A + 2B −⇀ 2C K1 = 2.81
2C −⇀ D K2 = 0.194
Calculate the value of the equilibrium constant for the reaction
D −⇀ A + 2B.
K = ?
Adding the two equations gives:
A + 2B = 2C K1=2.93
+
2C = D K2=0.258
Result:
A + 2B + 2C = 2C + D
K1 + K2
Remove 2С:
A + 2B = D
K1 + K2 = 2.93 + 0.258 = 3.188
Reversed reaction:
D = A + 2B
K3 = 1 / 3.188 = 0.314
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