Answer to Question #209311 in General Chemistry for mel

Question

For this reaction

2 H₂O (g) −⇀ 2 H₂ (g) + O₂ (g)

the equilibrium concentrations were found to be [H₂O] = 0.250 M, [H₂] = 0.410 M,

and [O₂] = 0.750 M.

What is the equilibrium constant for this reaction?

K_c = ?

Answer 1

K_c = $\frac{[H_2O]^2}{[H_2]^2 [O_2]}$ = $\frac{[0.250]^2]}{[0.410]^2 [0.750]}$

K_c = $\frac{0.0625}{0.1681×0.750}$ = $\frac{0.0625}{0.126075}$ = 0.495736

K_c = 0.496 approx