Question

If the initial reaction contains 1.73 M A, 1.01 M B, and 2.97 M C, calculate K_c for the new equilibrium reaction?

K_c = ?

Answer 1

$K_c= \frac{(C)^4}{(A)^6(B)^2}$

$K_c=\frac{[2.97]^4}{[1.73]^6×[1.01]^2}=2.8452$