Answer to Question #208422 in General Chemistry for Freya

Question

Question text

Consider the following: KClO₃ (122.55 g/mol), is prepared from KCl (74.55 g/mol) and O₂ gas (32.00 g/mol) by the following process:        

      

KCl   +  O₂  ------------->  KClO₃   (unbalanced reaction)

 

The amount of oxygen gas in grams that will be needed to produce 14.2 mL of KClO₃ (ρ = 2.34 g/mL) is

Answer 1

Amount of oxygen gas in grams=34.2g