Calculate the ΔH for the reaction: CS2 (l) + 2 O2 (g) 🡺 CO2 (g) + 2 SO2 (g)
ΔHreaction=∑ΔHproducts−∑ΔHreactants=−393.5+2(−296.8)−87.9=−1075kJ/mol\Delta{H}_{reaction}=\sum{\Delta{H_{products}-\sum\Delta{H}_{reactants}}}=-393.5+2(-296.8)-87.9=-1075kJ/molΔHreaction=∑ΔHproducts−∑ΔHreactants=−393.5+2(−296.8)−87.9=−1075kJ/mol
Answer: -1075 kJ/mol
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