A solution contains 0.25 g of sulfur dioxide in 1.00 dm3 of water. Which volume of sulfur dioxide, measured at 50 ï‚°C and a pressure of 1 ï‚´ 105Pa, must be added to 1.00 dm3 of water to produce this solution?
We use Mendeleev Klapeyron's formula for this problem:
PV=nRT
We must find volume :
V=nRT/P=1mol*8.314*(273K+50)/105kPa=
=18.36L
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