If the volume of a gas is 19.4 L at 4.99 atm, what is the volume at 1580 mmHg
V1=19.4 LP1=4.99 atmP2=1580 mmHg=2.078 atmP1V1=P2V2V2=P1V1P2=4.99×19.42.078=46.58 LV_1=19.4\;L \\ P_1=4.99 \;atm \\ P_2=1580 \;mmHg = 2.078 \;atm \\ P_1V_1=P_2V_2 \\ V_2= \frac{P_1V_1}{P_2} \\ = \frac{4.99 \times 19.4}{2.078} = 46.58 \;LV1=19.4LP1=4.99atmP2=1580mmHg=2.078atmP1V1=P2V2V2=P2P1V1=2.0784.99×19.4=46.58L
Answer: 46.58 L
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