If the volume of a gas is 19.4 L at 4.99 atm, what is the volume at 1580 mmHg
"V_1=19.4\\;L \\\\\n\nP_1=4.99 \\;atm \\\\\n\nP_2=1580 \\;mmHg = 2.078 \\;atm \\\\\n\nP_1V_1=P_2V_2 \\\\\n\nV_2= \\frac{P_1V_1}{P_2} \\\\\n\n= \\frac{4.99 \\times 19.4}{2.078} = 46.58 \\;L"
Answer: 46.58 L
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