2 Al + 3 FeSO3 -> Al2(SO3)3 + 3 Fe
if 136 g of aluminum are consumed, how many moles of iron (II) sulfite are consumed?
Moles of Al = "\\frac{136}{26.982}=5.04 moles"
Moles of "FeSO_3 = \\frac{3}{2}\u00d75.04=7.56 moles"
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