Question

2 Al + 3 FeSO₃ -> Al₂(SO₃)₃ + 3 Fe

if 136 g of aluminum are consumed, how many moles of iron (II) sulfite are consumed?

Answer 1

Moles of Al = $\frac{136}{26.982}=5.04 moles$

Moles of $FeSO_3 = \frac{3}{2}×5.04=7.56 moles$