For the reaction A(aq)+B(aq)----- C(aq)+D(aq) the equilibrium constant is 24.6 at 25 c and 37.6 at 50 c What is the value of satndard Gibbs free energy change (in Kj) of this reaction at 75 c
ΔG=VΔP−SΔT.
∆T= 50 - 25 = 25°C
= 37.6 - 24.6 = 13
= 0.75 *13 - 0.109*25
= 9.75 -2.725
= 7.025
Comments
Leave a comment