4)
Given: 2X(g) ⇌ Y(g) + Z(g) Ke = 15
If 2.0 mol of Y and 2.0 mol of Z are injected into an empty 4.0 L container, then find the resulting
equilibrium concentration of X.
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Kc=Qc=K_c=Q_c=Kc=Qc= [x]2[y][x][x]^2\over[y][x][y][x][x]2
x=x=x= (15.0)(2.0mol)(2.0mol)4.0L\sqrt{(15.0)(2.0mol)(2.0mol)}\over4.0L4.0L(15.0)(2.0mol)(2.0mol)
x=x=x= 604\sqrt{60}\over 4460
x=x=x= 3.873mol/L3.873mol/L3.873mol/L
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