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Answer to Question #204481 in General Chemistry for Vin
Question #204481
Find the boiling point of a solution containing 45 grams of calcium chloride dissolved in 250 mL of solution.
Expert's answer
"Tb = Kf \u00d7 M"
Kf= 2.53
Moles= 45/111= 0.405moles
M=( 0.405× 250)/1000
M= 0.101M
Tb= 25.3× 0.101
Tb= 25°C
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