please show steps, formula:
8 a. A photon with enough energy, 5.1 electron volts (eV) of energy, will eject an electron from a piece of gold! What frequency and wavelength do light with this energy have? Note: 1eV = 1.60 ×10-19 J
b. Recalling the information from question 8a, what would happen if you were to shine a light of 6.5 eV on the gold surface? How is this the same or different from using light of 3.0 eV? What if the metal was Cesium (Φ= 2.1eV) or Platinum (Φ= 6.35eV) instead?
The answer to your question is provided in the image:
Comments
Leave a comment