Question

A gas takes up a volume of 17 L, has a pressure of 2.3 atm, and a temperature of 299 K. If the temperature raised to 350 K and pressure is lowered at 1.5 atm, what is the new volume of gas?

Answer 1

$P_1=2.3 atm$

$V_1=17 l$

$T_1=299 K$

$P_2=1.5 atm$

$T_2=350 K$

Let $V_2=V_2$

Now:

$\dfrac{P_1V_1}{T_1} = \dfrac{P_2V_2}{T_2}$

$V_2= \dfrac{2.3\times17 \times350}{1.5\times299}=30.51l$