Question #203921

A 30.0 L sample of nitrogen inside a rigid, metal container at 20.0 °C is placed inside an oven whose temperature is 50.0 °C. The pressure inside the container at 20.0 °C was at 3.00 atm. What is the pressure of the nitrogen after its temperature is increased to 50.0 °C?



1
Expert's answer
2021-06-07T03:13:16-0400

V=constant=30.0  LT1=20+273=293  KT2=50+273=323  Kp1=3.0  atmp1T1=p2T2p2=p1×T2T1=3.0×323293=3.3  atmV=constant=30.0 \;L \\ T_1 = 20 +273 = 293 \;K \\ T_2 = 50 + 273 = 323 \;K \\ p_1= 3.0 \;atm \\ \frac{p_1}{T_1}= \frac{p_2}{T_2} \\ p_2= \frac{p_1 \times T_2}{T_1} \\ = \frac{3.0 \times 323}{293} \\ = 3.3 \;atm

Answer: 3.3 atm


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