A 30.0 L sample of nitrogen inside a rigid, metal container at 20.0 °C is placed inside an oven whose temperature is 50.0 °C. The pressure inside the container at 20.0 °C was at 3.00 atm. What is the pressure of the nitrogen after its temperature is increased to 50.0 °C?
"V=constant=30.0 \\;L \\\\\n\nT_1 = 20 +273 = 293 \\;K \\\\\n\nT_2 = 50 + 273 = 323 \\;K \\\\\n\np_1= 3.0 \\;atm \\\\\n\n\\frac{p_1}{T_1}= \\frac{p_2}{T_2} \\\\\n\np_2= \\frac{p_1 \\times T_2}{T_1} \\\\\n\n= \\frac{3.0 \\times 323}{293} \\\\\n\n= 3.3 \\;atm"
Answer: 3.3 atm
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