Supposed if 1 gram of potassium hydroxide was dissolved in 1litre of water, what is the concentration?
Answer:-
[KOH]=[K+]=[OH−]=1×100056×1000=0.0178M[KOH]=[K^+]=[OH^-]=\frac{1\times1000}{56\times1000}=0.0178M[KOH]=[K+]=[OH−]=56×10001×1000=0.0178M
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments