Question #203856

Supposed if 1 gram of potassium hydroxide was dissolved in 1litre of water, what is the concentration?


1
Expert's answer
2021-06-07T03:12:13-0400

Answer:-

[KOH]=[K+]=[OH]=1×100056×1000=0.0178M[KOH]=[K^+]=[OH^-]=\frac{1\times1000}{56\times1000}=0.0178M


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