Answer to Question #202827 in General Chemistry for Jagjit Singh

Question

When sodium chloride reacts with a silver nitrate silver chloride precipitates what mass of a AgCl it’s produce from 75.0 g of AgNO₃

Answer 1

NaCl+AgNO₃→AgCl+NaNO₃

Mole ratio = 1:1

Molar Mass of AgNO₃ = 169.87

= 75/169.87

= 0.442 mol

Molar Mass of AgCl = 143.32

= 143.32 × 0.442

= 63.278g