If you need 25,000 A of current to carry out electrolysis for 15 minutes, what voltage would you need if you are to use 1.7 kWh for the process?
Solution
E=QV
Q=I"\\times" t
t=15"\\times" 60=900 sec
2500"\\times" 900
Q=22.5"\\times10"6
E=P"\\times" t
converting 1.7kwh to joules
E=1.7"\\times3.6\\times10^6\\times900"
E=QV
therefore V="\\frac{E}{V}"
V="\\frac{1.7\\times{3.6}\\times{10^6}\\times{900}}{22.5\\times{10^6}}"
v=244.5
Comments
Leave a comment