Question

If you need 25,000 A of current to carry out electrolysis for 15 minutes, what voltage would you need if you are to use 1.7 kWh for the process?

Answer 1

Solution

E=QV

Q=I$\times$ t

t=15$\times$ 60=900 sec

2500$\times$ 900

Q=22.5$\times10$⁶

E=P$\times$ t

converting 1.7kwh to joules

E=1.7$\times3.6\times10^6\times900$

E=QV

therefore V=$\frac{E}{V}$

V=$\frac{1.7\times{3.6}\times{10^6}\times{900}}{22.5\times{10^6}}$

v=244.5