A sample of an oxide of copper
contains 8 g of copper combined with 1 g
of oxygen. Find the empirical formula
Cu=8/63.546=0.126/0.0625=2Cu = 8/63.546 = 0.126/0.0625 = 2Cu=8/63.546=0.126/0.0625=2
O=1/16=0.0625/0.0625=1O = 1/16 = 0.0625/0.0625= 1O=1/16=0.0625/0.0625=1
The empirical formula of the Compound is therefore, Cu2OCu_2OCu2O
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