Question

Nitric acid is formed by the reaction of nitrogen dioxide with water: 3NO₂(𝑔) + H₂O(ℓ) → NO(𝑔) + 2HNO₃(𝑎𝑞) How many grams of nitrogen monoxide, NO, are produced when 180.2 g of H₂O react with nitrogen dioxide?

Answer 1

First we must calculate the amount (in moles) of water:

$n(H_{2}O)=\frac{m(H_{2}O)}{M(H_{2}O)}=\frac{180.2g}{18.02g/mol}=10.00mol;$

Now, the amount (in moles) of nitrogen monoxide would be the same as that of water reacted:

$n(NO)=n(H_{2}O)=10.00mol;$

Finally, we can calculate the mass of the nitrogen monoxide formed:

$m(NO) = n(NO)\cdot M(NO)=10.00mol\cdot 30.01g/mol=300.1g.$