Question #201798

How many g of Co(NO2)2 • 5 H2O are needed to make 432 mL of a 1.2 M solution?


1
Expert's answer
2021-06-02T06:04:34-0400

M=1.2MM=1.2M

V=432mlV=432ml


M=molesvolume(ml)×1000M=\dfrac{moles}{volume(ml)} \times1000


1.2=moles432×10001.2= \dfrac{moles}{432} \times 1000


moles=0.518moles= 0.518

Now:

weight=moles×molarweight=moles \times molar massmass

weight=0.518×210=108.78gmweight= 0.518 \times 210=108.78 gm



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