How many g of Co(NO2)2 • 5 H2O are needed to make 432 mL of a 1.2 M solution?
M=1.2MM=1.2MM=1.2M
V=432mlV=432mlV=432ml
M=molesvolume(ml)×1000M=\dfrac{moles}{volume(ml)} \times1000M=volume(ml)moles×1000
1.2=moles432×10001.2= \dfrac{moles}{432} \times 10001.2=432moles×1000
moles=0.518moles= 0.518moles=0.518
Now:
weight=moles×molarweight=moles \times molarweight=moles×molar massmassmass
weight=0.518×210=108.78gmweight= 0.518 \times 210=108.78 gmweight=0.518×210=108.78gm
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