Answer to Question #201364 in General Chemistry for Layla

Question

250mL of a solution of HNO3 0.02mol/L are mixed with 150mL of a solution 

of NaOH 0.1mol/L. 

1. Write the equation of the reaction. 

2. Calculate the pH of the final mixture.

Answer 1

1. HNO3 + 2NaOH ->> NH3 + H2O + Na2

2. Molar Mass of HNO3 = 63.01

250/63.01

= 3.97 moles

Molar Mass of NaOH = 37.999

= 15/37.999

= 0.395

= 3.97/0.395

= 10.1

Log 10.1

PH= 1