Answer to Question #201170 in General Chemistry for caden

Question

 A container holds a mixture of gases with the following partial pressures: PO₂ = 40.3 kPa, PCO₂ = 0.89 kPa, PN₂ = 180.3 kPa, and Ptotal = 222.8 kPa. Calculate the pressure of the other gases as described by Dalton's law of partial pressures.

Answer 1

As per the Dalton’s law of partial pressure, the total pressure of the mixture of gases is equal to the sum of the pressure of each gas when they are kept alone.

The expression to determine the total pressure in accordance with the Dalton’s law of partial pressure is shown below.

P_total=P_Oxygen +P_{Carbon dioxide} +P_Nitrogen+P _Other

The pressure of the other gases is calculated as follows:-

$222.8kPa=40.3kPa+0.89kPa+180.3kPa+$

P_Other

P_Other=222.8kPa-(40.3kPa+0.89kPa+180.3kPa)

$=1.31kPa$

Thus, the pressure of other gases is 1.31 kPa.