Answer to Question #200350 in General Chemistry for Peace Clement

Question

Butane, C4H10, is an easily liquefied gaseous fuel. Calculate the density of butane gas at 0.897 atm and 24°C. Give the answer in grams per liter

Answer 1

$T = 273+24=297 K.$

$R= 0.082$

$P=0.897$ atm

PV = RT

$V=\frac{RT}{P}$

$V=\frac{0.082×297}{0.897}= 26.97= 26970cm^3/mole$ =

Molar mass of $C_4H_{10}= 56g/mole$

Density $= \frac{56}{26970}= 0.002 g/cm^3$