C3H8 + 5O2 --> 3CO2 + 4 H2O
Using the above reaction, calculate how many grams of H2O will be made if 195.0 g of O2 is reacted?
MM(O2) = 32 g/mol
n(O2) "= \\frac{195}{32}=6.093 \\;mol"
According to the reaction:
n(H2O) "= \\frac{4}{5}n(O_2) = \\frac{4}{5} \\times 6.093 = 4.875 \\;mol"
MM(H2O) = 18 g/mol
m(H2O) "= 4.875 \\times 18 = 87.75 \\;g"
Answer: 87.75 g
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