N 2 react to produce magnesium nitride , Mg 3 N 2 If the reaction is done in a closed system , what will be the mass of the product ? evidence and A 39 combination of Magnesium Mg and nitrogen gas reasoning to back up your claim
N2+3Mg=Mg3N2
So n(N2)=1mol
n(Mg)=1mol
Mole (N2)after reaction=1mol/1=1mol
Mole(Mg)=1mol/3=0.33mol
n(Mg)=n (Mg3N2)=0.33mol
m (Mg3N2)=0.33mol×100g/mol=33g
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