what is the number of molecules present in 0.062 mol of acetic acid, CH₃COOH
1 mole contains 6.022×10236.022 \times 10^{23}6.022×1023 atoms
Hence,
0.0620.0620.062 mole contains =0.062×6.022×1023= 0.062 \times 6.022 \times 10^{23}=0.062×6.022×1023 =0.37×1023=0.37 \times 10^{23}=0.37×1023
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