The cell represented below was set up under standard conditions.
Pt|Fe2+(aq), Fe3+(aq)||Tl3+ (aq),Tl+ (aq)|Pt Cell e.m.f. = + 0.48 V
(i) Deduce the standard electrode potential for the following half-reaction.
Tl3+(aq) + 2e– → Tl+ (aq)
(ii) Write an equation for the spontaneous cell reaction.
(i) ETi3+/Ti+=0.48+0.77=1.25 V
(ii) 2Fe3+ + Ti+ = 2Fe2+ + Ti3+
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