Given the following data, calculate the ∆H for the reaction: CaC₂(s) + 2H₂O(l) → Ca(OH)₂(aq) + C₂H₂(g).
Data:
Ca(s) + 2C(graphite) -> CaC2(s) delta H= -62.8 kJ
Ca(s) + 1/2O2(g) -> CaO(s) delta H= -635.5 kJ
CaO(s) +H2O(l) -> Ca(OH)s (aq) delta H= -653.1 kJ
C2H2(g) + 5/2O2(g) -> 2CO2(g) + H2O(l) delta H= -1300. kJ
C(graphite) + O2(g) -> CO2(g) delta H= -393.5 kJ
"\u0394H= -712.8 kJ"
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